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0=6w^2+7w-25
We move all terms to the left:
0-(6w^2+7w-25)=0
We add all the numbers together, and all the variables
-(6w^2+7w-25)=0
We get rid of parentheses
-6w^2-7w+25=0
a = -6; b = -7; c = +25;
Δ = b2-4ac
Δ = -72-4·(-6)·25
Δ = 649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{649}}{2*-6}=\frac{7-\sqrt{649}}{-12} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{649}}{2*-6}=\frac{7+\sqrt{649}}{-12} $
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